when the dice is thrown find the probability of getting odd number or even number square number prime number odd number multiple of 4.
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*ANSWER*
A dice is thrown
s={1,2,3,4,5,6}
n(s)= 6
A: getting odd number
A={1,3,5}
n(A)= 3
P(A)= n(A)/n(S)
= 3/6
= 1/2
B: getting even number
B={2,4,6}
n(B)= 3
p(B)= n(B)/ n(S)
= 3/6
=1/2
C: getting a square number
C={ 4 }
n(C)= 1
p(C)=n(C)/n(S)
= 1/6
D: getting a prime number
D={ 2,3,5}
n(D)= 3
P(D)= n(D)/ n(S)
=3/6
=1/2
E: getting a multiple of 4
E={4}
n(E)= 1
p(E)= n(E)/ n(S)
=1/6
I hope this helps...
please make this as the brainliest answer....
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