Question

if the root of the equation x²-8x+m=0 exceeds the other by 4 then the value of m is ​

Answer 1

Answer:

ur ans- is

x^2-8x+m=0

8/2=4

make the square

and set it equal to the difference 4

(x-4)^2=4

multiply it out

x^2-8x+16=4

x^2-8x+12=0

m=12

I hope it's helpful 4 u

Answer 2

Answer:

x2-8x+m=0+4

x2-8x+m=4

x(x-8)+m=4