Question

If the roots of 2x^2-6x+k=0 are real and eequalfind k?

Answer 1

Hope it will help you.

Please Please make me brainliest

Answer 2

${\huge{\mathfrak{\red{G}{iven}}}}$

The roots of ${2x^2 -6x + k = 0}$ are real and equal.

${\huge{\mathfrak{\red{T}{o\:find}}}}$

The value of k

${\huge{\mathfrak{\red{B}{rainliest\:answer}}}}$

${2x^2-6x+k =0}$

a = 2; b = -6; c = k

Now, if roots are real and equal

Then, D = ${b^2-4ac =0}$

-» ${{-6}^2-4(2)(k) = 0}$

-» ${36 - 8k = 0}$

-» ${9 - 2k = 0}$

-» ${2k = 9}$

-» ${k = 9/2}$

${\huge{\red{\boxed{k = 9/2}}}}$

${\huge{\mathfrak{Be\:Brainly}}}$