If the roots of 5x^2-4kx+5=0 are equal then the values of k are
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Answered by
4
Comparing with the general form we get a=5,b=4,c=5.
Sum of roots i:e m+m=-(-4k/5)=4k/5
2m=4k/5
m=2k/5
Product of roots =m×m=5/5
m²=1
m=±1
Thus
2k/5=±1
Thus k=±5/2
Sum of roots i:e m+m=-(-4k/5)=4k/5
2m=4k/5
m=2k/5
Product of roots =m×m=5/5
m²=1
m=±1
Thus
2k/5=±1
Thus k=±5/2
Answered by
2
By comparing above equation with ax^2+bx+c=0, we get
a=5, b=-4k and c=5
D=b^2-4ac
=(-4k)^2-4(5)(5)
=16k^2-100=0 {since, roots are equal}
=k^2=100/16
=k=+10/4,-10/4
a=5, b=-4k and c=5
D=b^2-4ac
=(-4k)^2-4(5)(5)
=16k^2-100=0 {since, roots are equal}
=k^2=100/16
=k=+10/4,-10/4
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