if the roots of ax2+2bx+c=0 are equal and real, prove that a:b=b:c
Please it is urgent :(
Answers
Answered by
6
given that roots of a polynomial are equal and real ,this means that it's discriminant I.e. b^2-4ac=0 ...-(1)
here,b=2b,a=a and c=c
putting these values in equation 1 we get:
(2b)^2-4ac=0
4b^2-4ac=0
4(b^2-ac)=0
b^2-ac=0 or ac-b^2=0 ...-(2)
now given that a:b=b:c
a/b=b/c
a/b-b/c=0
taking lcm,
(ac-b^2)/bc=0
ac-b^2=0 ...-(3)
both equations 2 and 3 are equal to zero .
hence,proved.
thank u,hope it helps!^_^
here,b=2b,a=a and c=c
putting these values in equation 1 we get:
(2b)^2-4ac=0
4b^2-4ac=0
4(b^2-ac)=0
b^2-ac=0 or ac-b^2=0 ...-(2)
now given that a:b=b:c
a/b=b/c
a/b-b/c=0
taking lcm,
(ac-b^2)/bc=0
ac-b^2=0 ...-(3)
both equations 2 and 3 are equal to zero .
hence,proved.
thank u,hope it helps!^_^
HimanshiKankane:
if my answer was helpful than please mark it as the brainliest !thank u!
how
u will get an Option to 'mark as brainliest' when u get two answers for your question
than u can mark!
Similar questions