Question

if the roots of equation ax2+bx+c=0 are equal in magnitude but opposite in sign then the value of b will be

Answer 1

Let the two roots be alpha and beta.
Alpha=-beta.
Alpha + beta =-b/a
=-beta+beta = -b/a
= 0 = -b/a
= -b = 0
= b =0.


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Answer 2

Step-by-step explanation:

let the two roots be alpha and beta

it is given that the roots are equal in magnitude but opposit in sign

therefore alpha=-beta____(1)

alpha +beta= b/a

-beta+beta=b/a......(from eqn 1)

0=b/a

therefore, it implies that b=0.