Question

if the roots of equation (b-c)x²+(c-a)x+(a-b)=0 are equal then 2b=a+c i.e., a, b, c are in AP .​

Answer 1

Answer:

Step 1: Root(9.5) = root(9+ 0.5) 9 is 3 squared. Make the base length AB be 3 easily drawn with a ruler and then draw a line perpendicular to our number line from point B. Now from B we have to mark point C on the dotted line which will be root(0.5) away from B.

Answer 2

If the roots of the equation (b-c)x2+(c-a)x+(a-b)=0 are equal, then prove that 2b=a+cRead more on Sarthaks.com - https://www.sarthaks.com/34526/if-the-roots-of-the-equation-b-c-x-2-c-a-x-a-b-0-are-equal-then-prove-that-2b-a-c