Math, asked by dhyan3632, 3 months ago

if the roots of equation x²-5x+16=0 are a,b and roots of equation x²+px+q=0 are a²+b², ab/2 then
(a)p=1,q=-56
(b)p=-1,q=-56
(c)p=1,q=56
(d)p=-1,q=56​

Answers

Answered by kaushalmahesh2004
1

Answer:

if the roots of equation x²-5x+16=0 are a,b and roots of equation x²+px+q=0 are a²+b², ab/2 then

(a)p=1,q=-56

(b)p=-1,q=-56

(c)p=1,q=56

(d)p=-1,q=56

Step-by-step explanation:

if the roots of equation x²-5x+16=0 are a,b and roots of equation x²+px+q=0 are a²+b², ab/2 then

(a)p=1,q=-56

(b)p=-1,q=-56

(c)p=1,q=56

(d)p=-1,q=56

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