Question

if the roots of equations has real and equal than find value of m (m-12)x²+2(m-12)x+2=0​

Answer 1

Answer:

For real and equal roots, the Discriminant should be 0. So the value is either 12 or 14 for the required situation

Answer 2

Here a = (m-12), b = 2(m-12) and c = 2

ATQ :

${b}^{2} - 4ac = 0 \\ \\ = > {(2(m - 12))}^{2} - 4 \times (m - 12) \times 2 = 0\\ \\ = > 4 ({m}^{2} - 24m + 144) - 8m + 96 = 0 \\ \\ = > 4 {m}^{2} - 96m + 576 - 8m + 96 = 0 \\ \\ = > 4 {m}^{2} - 104m + 672 = 0 \\ \\ = > {m}^{2} - 26m + 168 = 0 \\ \\ = > {m}^{2} - 14m - 12m + 168 = 0 \\ \\ = > m(m - 14) - 12(m - 14) = 0 \\ \\ = > (m - 14) (m- 12) = 0$

Values of m = 14 and 12 ✔✔

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