Question

If the roots of $\frac{ x^{2} -bx}{ax-c} = \frac{K-1}{K+1}$ are numerically equal but opposite in sign, then K =
1) c
2) $\frac{1}{c}$
3) $\frac{a+b}{a-b} }$
4)$\frac{a-b}{a+b} }$

Answer 1

QUADRATICS RESOLUTION