If the roots of the equation 2x²-5x+b=0 are in the ratio of 2:3 then find the value of b ?
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Answer:
3
Step-by-step explanation:
Let α and β be the roots of the equation.
α : β = 2:3 => α/β = 2/3 => α = 2/3 * β.
Sum of roots = α + β = -b/a = -5/2
Product of roots = αβ = c/a = b/2
Substitute value of α in first equation.
α + β = -5/2
2β/3 + β = -5/2
5β/3 = - 5/2
β = -3/2, α = -1
//Now substitute α and β values in 2nd equation.
αβ = b/2
(-3/2)(-1) = b/2
=> b/2 = 3/2
=> b = 3
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