If the roots of the equation 4^3 – 12^2 + 11x + k = 0
are in arithmetic progression, then k is equal to........
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For this polynomial Sum of roots =12/4 = 3 ... roots are 1/2,1,3/2 So product of roots is 3/4 -k/4=3/4 k=-3. ... possible values of p if x²+(p-2) x+p+1=0 has equal roots?
It's about summation of roots = -b/a & product of roots = c/a, which gives k= -3. More
For this polynomial Sum of roots =12/4 = 3 =(a-d)+(a)+(a+d) =3a=3 -%3Ea=1 a(a-d)+a(a+d)+(a-d)(a ...
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