If the roots of the equation X^2 - px+q=0 differ by Unity, then prove that p^2=1+4q
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Answered by
33
Hi Mate!!!
Let the roots be a and b
a - b = 1. as given roots differ by unity
a + b = p
ab = q
a - b = √ {( a+b)² - 4ab}
1 = √{ ( -p)² - 4( q ) }
Squaring both sides
p² = 1+4q. hence, proved
Have a nice time
Let the roots be a and b
a - b = 1. as given roots differ by unity
a + b = p
ab = q
a - b = √ {( a+b)² - 4ab}
1 = √{ ( -p)² - 4( q ) }
Squaring both sides
p² = 1+4q. hence, proved
Have a nice time
amitasardana14p9l1n7:
Thnx bro
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20
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