Question

If the roots of the equation x^-8kx+2k=0 are equal find the value of k

Answer 1

an equation has equal roots only if it's discriminant =0
$\sqrt{ (- 8k) {}^{2} - 4(1)(2k) } = 0 \\ 64 {k}^{2} = 8k \\ k = 0 \: or \: (1 \div 8)$

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :- ----6--

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.