Question

If the roots of x² + kx + k = 0 are real and equal, what is the value of k?

Answer 1

hope it will help you!!

Answer 2

Answer:

Values of k are 0 and 4.

Step-by-step explanation:

Given that roots of $x^2 + kx + k = 0$ are real and equal. we have to find the value of k.

The general form of quadratic equation is

$ax^2+bx+c$

Compare above with given equation$x^2 + kx + k = 0$, we get

a=1, b=k, c=k

As the roots of given equation are equal

⇒ Discriminant is 0.

i.e $b^2-4ac=0$

⇒ $k^2-4k=0$

⇒ $k(k-4)=0$

⇒ $k=0, 4$

hence, values of k are 0 and 4