Question

if the scalar product of two vectors is equal to the magnitude of their vector product
find the angle between them. (Ans: 45°)​

Answer 1

Answer:

Explanation:

Hope it helps mark it as best...!!

Answer 2

Concept Introduction: Vectors are very useful in doing advanced physics numericals.

Given:

We have been Given: The scalar product of two vectors is equal to the magnitude of their vector product.

To Find:

We have to Find: Find the angle between them.

Solution:

According to the problem,

$a.b = |a \times b| \\ |a| . |b| \cos( \alpha ) = |a| . |b| \sin( \alpha ) \\ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = 1 \\ \tan( \alpha ) = 1 \\ \alpha = 45 \: degree$

Final Answer: The angle between them is

$45 \: degree$

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