If the second and third term of an A.P are 14 and 18 respectively, then find its 12th term
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Answered by
5
Step-by-step explanation:
Second term =14
Third term =18
so, T2= 14 and T3=18
a+d=14 and a+ 2d=18
a=14-d =>14-d+2d=18
=>14+d=18
=>d=4
So, a =10
Hence 12th term= a+11d
=>10+11×4
=>10+44
=>54
Answered by
1
Step-by-step explanation:
54
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