Question

if the second term of an A.P. is -15 and third term 10,find tenth term of its​

Answer 1

a+d=(-15) and a+2d=10

so a+2d-(a+d)=10-(-15)

d=25 and a=-40

So 10th term is a+9d

-40+9×25

=225-40

=185

Thanks a lot and please mark me as brainliest

Answer 2

Answer:

185

Step-by-step explanation:

$so \\a_{2}=-15\\a_{3}=10\\a_{3}-a_{2}=25=d\\so a_{1}=a_{2}-d=-40\\so a_{10}=a_{1}+9d=-40+225=185$