If the semicircle drawn with one side of a triangle as diameter passes through the opposite vertex, then the measure of the angle at the vertex is_______ degree
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Answer:90 Degrees, for a half circle, the intercepted arc measures 180°, so each corresponding inscribed angle is half that.
Explanation:
∆OBA and ∆OBC are isosceles triangles, and by the equality of the base angles of an isosceles triangle, ∠OBC = ∠OCB and ∠OBA = ∠OAB.
Let α = ∠BAO and β = ∠OBC. The three internal angles of the ∆ABC triangle are α, (α + β), and β. Since the sum of the angles of a triangle is equal to 180°, we have
α + (α + β) + β = 180°
2α + 2β = 180°
2(α + β) = 180°
α + β = 90°
Hence, Angle ABC = 90°
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