If the set A has 3 elements and the set B = (3, 4, 5), then find the number of
elements in (AXB).
15 A 21 find GXH and HX G.
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To define the injective functions from set A to set B, we can map the first element of set A to any of the 4 elements of set B.
Then the second element can not be mapped to the same element of set A, hence, there are 3 choices in set B for the second element of set A.
Similarly there are 2 choices in set B for the third element of set A.
Hence the total number of injective functions are 4×3×2=24
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