If the seven term of an AP is 1/9 and its ninth term is 1/7 find its 63 rd term
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a+6d=1/9
a+8d=1/7
using elimination method
-2d=1/9-1/7
-2d=7-9/63
2d=2/63
d=1/63
a=1/9-6d
a=7-6/63
a=1/63
atq
63 th term will be
1/63+62*1/63
63/63
=1
will be the answer
a+8d=1/7
using elimination method
-2d=1/9-1/7
-2d=7-9/63
2d=2/63
d=1/63
a=1/9-6d
a=7-6/63
a=1/63
atq
63 th term will be
1/63+62*1/63
63/63
=1
will be the answer
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2
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