If U={1,2,3,4,5,6}, A={1,2,4},B={2,4,5} then clarify De-Morgan's laws.
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De morgan law = (AUB)'=(A' intersection B')
Here,
AUB = 1,2,4,5
Then (AUB)' = 3,6
A' = 3,5,6
B' = 3,6
(A' intersection B') = 3,6
therefore (A U B)'=(A' INTERSECTION B')
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Here,
AUB = 1,2,4,5
Then (AUB)' = 3,6
A' = 3,5,6
B' = 3,6
(A' intersection B') = 3,6
therefore (A U B)'=(A' INTERSECTION B')
Hope u like my answer
if so please mark me as brainelist
Lekhraj:
There are two laws and u have clarified only one
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