If the seventh term of an ap is 1/9 and its ninth term is 1/7,find its(63)rd term
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Tripathy
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Tripathy
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Nth term = a + (n-1)d
Seventh term = 1/9
a = 1/9 - (7-1)d....... (i)
Ninth term = 1/7
a= 1/7 -(9-1)d.......... (ii)
From (i) and (ii) .... Evaluate d by equalizing
Then find the value of a
Then for 63rd term
=> a+(63-1)d
Put values of a and d and find it out .
Simple .
If you have any problem solving this let me know by commenting on this answer.
Seventh term = 1/9
a = 1/9 - (7-1)d....... (i)
Ninth term = 1/7
a= 1/7 -(9-1)d.......... (ii)
From (i) and (ii) .... Evaluate d by equalizing
Then find the value of a
Then for 63rd term
=> a+(63-1)d
Put values of a and d and find it out .
Simple .
If you have any problem solving this let me know by commenting on this answer.
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