If the shadow of a building increases by 10 meters when the angle of elevation of the sun rays decreases from 70° to 60°, what is the height of the building?
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Answer:
Make two right-angled triangles,
let the base (length of shadow) of the first be x, and its base angle is 70°
let the base of the second be x+10, and label its base angle as 60°
For both let the height (the building) be h
from the first:
tan70 = h/x ---> h = xtan70
from the second:
tan60 = h/(x+10) ---> h = (x+10)tan60
then xtan70 = (x+10)tan60
xtan70 = xtan60 + 10tan60
xtan70 - xtan60 = 10tan60
x(tan70-tan60) = 10tan60
x = 10tan60/(tan70-tan60)
back in h = xtan70
h = 10tan60tan70/(tan70-tan60)
= appr 46.9 m
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