Question

If the shadow of a tower is 30m long,when the sun`s elevation is 30 what is the length of the shadow when sun`s elevation is 60

Answer 1

here is your answer...

Answer 2

in ∆ ABD

tan30 = AB/BD

1/√3 = H/30

30/√3 = H

$\frac{30}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{30 \sqrt{3} }{3}$

10√3 = H

In ∆ABC

tan60 = AB/BC

√3 = 10√3/BC

BC = 10√3/√3

BC = 10


The length of Shadow when sun's elevation is 60° is 10m