Question

if the shortest wavelength of hydrogen atom in Lyman series is x then the longest wavelength in patches series of He+ is​

Answer 1

109678 is a constant,lets say = ;

,the series starts from n1 to n2;

 

x is the wavelength for the last line(shortest wavelength) in lyman series,

therefore,n1=1 to n2=(infinity);

    (1/x)=[(1/1) – (1/)]    =    (1 - 0) = 

      = 1/x              

 

For wavelength of first line of balmer series,

n1=2 to n2=3  ;lets say the wavelength to be found be = ;



Substituting the value

Answer 2

Answer:

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