If the side of a rhombus is 10 cm and one diagonal is 16 cm, then find the area of the rhombus.
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Answer:
96 square cm
Step-by-step explanation:
All sides are equal in a Rhombus. So all the four sides are 10 cm each.
The two diagonals divide the Rhombus into four right triangles.
If we take one such triangle, the hypotenuse will be 10cm. and one of its sides is 8cm(16cm is shared by two triangles. Therefore one triangle has a side of 8cm).
By pythagorean theorem, the third side of the triangle(which is the half of the other diagonal) is found to be 6.
The full length of the other diagonal is 12cm(6+6).
The area of the Rhombus =
(1st diagonal × 2nd diagonal)÷2
Therefore,
Area = (16×12)÷2
= 96 square cm
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