Question

If the side of a square is 4 m and it is converted into a rhombus having one diagonal as 2√7 m,
find the length of other diagonal and area of rhombus.​

Answer 1

Answer:

6√7 sq m

Step-by-step explanation:

in a rhombus diagonals( d1, d2) bisect each other perpendicularly

s= 4m

d1 = 2√7 m,

s^2 = (d1/2)^2+(d2/2)^2

4^2= (√7)^2 + (d2/2)^2

16= 7+(d2/2)^2

16-7= (d2) ^2/4

(d2)^2= 9×4=36= 6^2

d2= 6 m

area of rhombus = (d1d2) /2

=( 2√7×6) /2

= 6√7 sq m