Question

If the side of a square is increased by 20%, then how much
per cent does its area get increased?​

Answer 1

Answer:

Side is increased by 20%

let initial length of side be x.

increased length =x+20%(x)

=1.2x

initial area = x(x)=x

2

increased area = (1.2x)(1.2x)=(1.44x

2

)

percent increase in area=

x

2

1.44x

2

−x

2

×100

=0.44×100

percentage increase in are =44%

Answer 2

Step-by-step explanation:

Let the side of the square be 'x'.

We know that Area = x^2.

Given that side of a square is increased by 20%.

=> Length of each side = x + 20% of x = 120x/100 = (6/5)x

New area = (6x/5)^2 = (36x^2/25)

Now,

Increase in area = (36x^2/25) - x^2

                           = (36x^2 - 25x^2)/25

                           = 11x^2/25

So, the % increase in area = (11x^2/25) * (100/x^2)

= > 1100/25

= > 44.

Therefore, Area is increased by 44%.

Hope this helps!