Question

If the side of a square is tripled , how many times will its area be as compared to the area of the original square? ​

Answer 1

let a be the side of a square

area of square = a^3 ...... (1)

if the side is tripled

then the side = 3a

area of square = (3a)^3 = 9a^3 = 9 area of the original square ( from equation (1))

Ans. The area is increased by 9 times

Hope it will help you

If you like it mark it as branliest

Answer 2

$\Large\underline\mathfrak{Question}$

If the side of a square is tripled , how many times will its area be as compared to the area of the original square?

$\Large\bold\star\underline{\underline\textbf{Formula\:used}}$

→ Area of Square = ( side * side) = (side)² .

$\Large\underline{\underline{\sf{Solution}:}}$

Let us assume That, side of square is = a cm.

Than,

→ Area of square = (a)² = a² cm². --------- Equation (1)

Now,

Given That, side is Tripled , That means 3 Times ,

So,

→ New side of Square = 3 * a = 3a cm.

→ New Area of Square = (3a)² = 9a² cm² . ------ Equation(2)

Now, dividing Equation (2), with Equation (1) , we get,

→ ( New Area of Square) / ( Area of square) = 9a² / a²

→ ( New Area of Square) / ( Area of square) = 9/1

Hence, New area of square will be 9 Times The area of Square .

$\rule{200}{4}$

$\bf\red\bigstar\underline\textbf{\blue{Extra}\:Brainly\: \pink{Knowledge}}\red\bigstar$

→The diagonals of a square bisect each other and meet at 90°.

→The diagonals of a square bisect its angles.

→Opposite sides of a square are both parallel and equal in length.

→All four angles of a square are equal.

→All four sides of a square are equal.

→The diagonals of a square are equal.

→ The perimeter of the square is given by :-

P = 4•Side.

→ The diagonal of a square is given by :-

D = √2•Side

→The area of a square is given by :-

A = (Side)²

→ The area of a square is also given by :-

A = (1/2)•(Diagonal)²

$\rule{200}{4}$