If the side of the rhombus is 10 cm and one diagonal is 16 cm, then find the area of the rhombus.
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Step-by-step explanation:
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hey mate here is ur ans
Step-by-step explanation:
let the rhombus be ABCD
AD= 10cm
.DB = 16 CM
CENTRE OF DIOGNAL IS O
OB = 16/2 = 8 CM diagonal of rhombus bisect each other.
using phythogoras theorem in triangle OAD
OA = √(AD²-OD²) = √100-64 = √36 = 6 CM
AC = 6×2 = 12 CM
area of rhombus = 1/2 d1×d2 = 1/2 ×16×12 = 96cm²
.hope it help u
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