if the sides of a rhombus is 6 and one of the angle of its of the Rhombus is 60 degree find the area of the Rhombus with give a good explanation detailed explanation to be the brainliest
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akddevil:
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Hey!!!
Here is your answer____________
Using trigonometry
If you are familiar with trigonometry, there is a handy formula when you know the length of a side and any angle:
area=s^2 sin a
where,
s is the length of any side
a is any interior angle
sin is the sine function
----------------------------------------------
given,
side of Rhombus is 6 unit ie. s = 6 unit
angle of Rhombus is 60° ie. a = 60°
area of rhombus (A),
A = s^2 x sin60°
A = (6)^2 x root3/2
A = 6 x 6 x root3/2
A = 6 x 3 x root3
A = 18 x root3 sq.unit
A = 18 x 1.732 sq.unit
A = 31.176 sq.unit
Hence, area of given rhombus is ,
A = 18 x root3 sq.unit
OR
A = 31.176 sq.unit
---------------------------------------------
Hope this answer will help u....
Here is your answer____________
Using trigonometry
If you are familiar with trigonometry, there is a handy formula when you know the length of a side and any angle:
area=s^2 sin a
where,
s is the length of any side
a is any interior angle
sin is the sine function
----------------------------------------------
given,
side of Rhombus is 6 unit ie. s = 6 unit
angle of Rhombus is 60° ie. a = 60°
area of rhombus (A),
A = s^2 x sin60°
A = (6)^2 x root3/2
A = 6 x 6 x root3/2
A = 6 x 3 x root3
A = 18 x root3 sq.unit
A = 18 x 1.732 sq.unit
A = 31.176 sq.unit
Hence, area of given rhombus is ,
A = 18 x root3 sq.unit
OR
A = 31.176 sq.unit
---------------------------------------------
Hope this answer will help u....
:)
in which class u are
12th
oh
u???
i am in 8std
ohk...
we can't takk here this is against the rule of brainly :(
ok
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