If the sides of a square are increased by 30 % find the percentage increase in its area
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Answered by
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Let side of square be "x"
=) So it's area = side × side
= x × x = x^2
=) new side of square = x + 30% of x
= x + 30/100 ×x
= x + 3x/10
= 13x/10
=) new area = 13x ×13x / 100
= 169x^2/100
increase in area = 169 x^2 /100 - x^2
= 69 x^2/ 100
% increase in area = 69x^2 ×100 /100x^2
= 69 % ans
___________________________________________.
=) So it's area = side × side
= x × x = x^2
=) new side of square = x + 30% of x
= x + 30/100 ×x
= x + 3x/10
= 13x/10
=) new area = 13x ×13x / 100
= 169x^2/100
increase in area = 169 x^2 /100 - x^2
= 69 x^2/ 100
% increase in area = 69x^2 ×100 /100x^2
= 69 % ans
___________________________________________.
Answered by
1
Answer:
69% is the correct answer
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