If the sides of a square lengthened byby 3cm,the area becomes 121cmsquare. find the perimeter of the original square
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Answered by
5
let the original side be x.
so, (x+3)^2=121
so,x+3=11
thus,x=(11-3)cm=8 cm
perimeter of a square=4x
=4*8=32cm
so, (x+3)^2=121
so,x+3=11
thus,x=(11-3)cm=8 cm
perimeter of a square=4x
=4*8=32cm
Answered by
2
hence the answer is 32cm
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