If the sides of a triangle are 11cm,15cm,16cm then the attitude to the longest side is ?
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Find the semi-perimeter:
p = ( 11 + 15 + 16 ) ÷ 2 = 21
Find the area:
Area = √p(p-a)(p-b)(p-c)
Area = √21(21 - 11)(21 - 15)(21 - 16)
Area = √6300
Area = 30√7 cm²
Find the altitude of the longest side:
Area = 1/2 x base x height
30√7 = 1/2 x 16 x height
30√7 = 8 x height
height = 30√7 ÷ 8 = (15√7)/4 or 9.92 cm
Answer: The altitude of the longest side is 9.92 cm
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