Math, asked by priyanshkoshta4128, 10 months ago

If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is
A. 90°
B. 180°
C. 270°
D. 360°

Answers

Answered by amitnrw
15

the sum of the three exterior angles  = 360°

Step-by-step explanation:

If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is

Exterior angle of a triangle = (sum of two opposite interior angle)

Sum of all three exterior angle = (∠A + ∠B)  + (∠B + ∠C)  + (∠C + ∠A)

= 2 ( ∠A + ∠B + ∠C)

= 2 * 180°

= 360°

Another method

three exterior angle would be

180°- ∠A , 180° - ∠B , 180° - ∠C

Sum of all three exterior angle = (180°- ∠A) + (180° - ∠B) +  (180° - ∠C)

= 540° - (  ∠A + ∠B + ∠C)

= 540° - 180°

= 360°

the sum of the three exterior angles  = 360°

option D is correct

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Answered by purushothamvajjula
1

Answer:

Step-by-step explanation: If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is

Exterior angle of a triangle = (sum of two opposite interior angle)

Sum of all three exterior angle = (∠A + ∠B)  + (∠B + ∠C)  + (∠C + ∠A)

= 2 ( ∠A + ∠B + ∠C)

= 2 * 180°

= 360°

Another method

three exterior angle would be

180°- ∠A , 180° - ∠B , 180° - ∠C

Sum of all three exterior angle = (180°- ∠A) + (180° - ∠B) +  (180° - ∠C)

= 540° - (  ∠A + ∠B + ∠C)

= 540° - 180°

= 360°

the sum of the three exterior angles  = 360°

option D is correct

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