Question

if the sides of a triangle ate a-1 cm 2√2 cm and a+1 cm then triangle is:​

Answer 1

Answer:

$★\sf \colorbox{god} {AB = (a - 1) \: cm}$

$★\sf \colorbox{god} {BC = 2} \sqrt{a} \: \sf \colorbox{god} {cm}$

$★\sf \colorbox{god} {CA = (a + 1 )\: cm}$

Hence,

$⇒ {AB}^{2} = (a - 1 {)}^{2} = {a}^{2} + 1 - 2a$

$⇒ {BC}^{2} = (2 \sqrt{a} {)}^{2} = 4a$

$⇒ {AC}^{2} = (a + b {)}^{2} = {a}^{2} + 1 + 2a$

$⇒ {AB}^{2} + {BC}^{2} = {a}^{2} + 1 - 2a + 4a$

$⇒ {AB}^{2} + {BC}^{2} = {a}^{2} + 1 + 2a$

$∴ {AC}^{2} = {AB}^{2} + {BC}^{2}$

So,

$\sf \colorbox{god} {∆ABV is a Right angled triangle}$

• Right Option is (d) Right angled

$\\ \\ \\ \\ \sf \colorbox{lightgreen} {\red★ANSWER ᵇʸɴᴀᴡᴀʙ}$