Question

if the sides of triangle are 11cm‚60cm‚61cm then area of triangle is​

Answer 1

Answer:

= (61 + 60 + 11)cm Therefore s = 1322 cm = 66cm Here a = 61cm , b = 60cm and c = 11cm Then by heron's formula,Area of triangle PQR = √(s(s ..

Answer 2

》To find -

Area of triangle.

》Given -

aa = 60\:cm60cm

bb = 61\:cm61cm

cc = 11\:cm11cm

ss = \frac{a+b+c}{2}

2

a+b+c

= \frac{60+61+11}{2}

2

60+61+11

= 66\:cm66cm

》Solution -

To find the area of a triangle, when all the sides are given, we use Herons Formula.

i.e.,

AA = \sqrt{s(s-a)(s-b)(s-c)}

s(s−a)(s−b)(s−c)

where a, b and c are the sides of the triangle and s is the sum of all the sides divided by 2.

⇒ AA = \sqrt{s(s-a)(s-b)(s-c)}

s(s−a)(s−b)(s−c)

⇒ AA = \sqrt{66(66-60)(66-61)(66-11)}

66(66−60)(66−61)(66−11)

⇒ AA = \sqrt{66(6)(5)(55)}

66(6)(5)(55)

⇒ AA = \sqrt{108900}

108900

⇒ AA = 330\:{cm}^{2}330cm

2

So, the area of the triangle is 330\:{cm}^{2}330cm

2

.