Question

If the sixth terms of AP is zero then show that 33rd term is three times its 15th terms.

Answer 1

Hey mate

Here is ur answer

6th term = a + 5d = 0
a = -5d
33rd term = a + 32d
= (-5d) + 32d
= -5d + 32d
= 27d
15th term = a + 14d
= (-5d) + 14d
= -5d + 14 d
= 9d

33rd term = 27d
15th term = 9d
When compared,
27d = 3*9d
This means
33rd term = 3* 15th term
HENCE PROVED

Answer 2

t6=0
a+5d=0
a=-5d----(i)
now
33rd term=a+32d
putting the value of a from equation (i) we get
t33=-5d+32d
=27d----(ii)
now,
t15=a+14d
=-5d+14d
=9d-----(iii)
from equation (ii) and (iii)
3(t15)=(t33)
proved.
hope this helps you
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