if the size of a virtual image formed by a concave mirror of focal length 15cm is twice the size of the object then size of the object is
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f=-15cm
u=-u
v=2u
from
1/v+1/u=1/f
we get u=7.5cm
now
m/n=v/u=2
so m=15cm(Ans)
f=-15cm
u=-u
v=2u
from
1/v+1/u=1/f
we get u=7.5cm
now
m/n=v/u=2
so m=15cm(Ans)
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