if the slope of y = 3x2 + a3 , maximum at x=1/2 find a?
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Answer:
3
Step-by-step explanation:
y=3x2+3sinx
⇒dxdy=6x+3cosx
Thus slope of tangent to the given curve at x=0 is
=dxdy∣∣∣∣∣x=0=(6x+3cosx)∣∣∣∣∣x=0=6(0)+3cos0=0+3⋅1=3
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