Question

If the smaller of two consecutive odd integers is doubled, the result is 7 more than the larger integer. Find the two integers.

Answer 1

let the two consecutive odd no.s be 2x+1 and 2x+3., then, ATQ,
2(2x+1) = 7+ (2x+3).
4x+2. = 7+(2x+3)
4x-(2x+3) = 7-2
4x-2x-3=5
2x=5+3
x=8/2
X=4
then,
smaller integer(2x+1) is...9 and other one (2x+3) is 11.[ by Putting the value of x]

Answer 2

Given:

When the smaller of two consecutive odd integers is doubled, the result becomes 7 more than the larger integer.

To find:

The two integers.

Solution:

The two integers are 9 and 11.

To answer this question, we will follow the following steps:

Let the smaller of two consecutive odd integers be x.

So, the larger of two consecutive odd integers will be x + 2.

Now,

According to the question,

we have,

$2x = (x + 2) + 7$

On solving the above, we get

$2x = x + 9$

$x = 9$

which is the smaller of two consecutive odd integers.

Now,

On putting the value of x = 9 in x + 2, we get

Larger of two consecutive odd integers

= 9 + 2

= 11

Hence, the two consecutive odd integers are 9 and 11.