Question

If the solubility of PbCl₂ at 25°C is 6.3 × 10⁻³ mole/litre, its solubility product at that temperature is
(a) (6.3 × 10⁻³) × (12.6 × 10⁻³)²
(b) (6.3 × 10⁻³)² × (12.6 × 10⁻³)
(c) (6.3 × 10⁻³) × (12.6 × 10⁻³)
(d) (12.6 × 10⁻³) × (12.6 × 10⁻³)

Answer 1

(6.3×10^-3)×(12.6×10^-3)^2