Question

If the solubility product of CuS is 6* 10^-16, calculate the maximum molarity of CuS in aqueous solution.

Answer 1

Hi there!!

Ksp = 6 ×10^-16

CuS ⇔ Cu^2+ + S^2-

Ksp = [Cu^2+] [S^2-]

6×10^-16 = x × x where "x" is the solubility in mol L^-1, i.e. molarity.

⇒ x² = 6×10^-16
 ∴ x = √6 × 10^-8
       = 2.44 × 10^-8 mol L^-1
       = 2.44 × 10^-8 M

Hope it helps...

Answer 2

Hey !!

Maximum molarity of CuS in aqueous solution = Solubility of CuS in mol L⁻¹

If S is the solubility of CuS in mol L⁻¹ then,

            CuS ⇄ Cu²⁺ + S²⁻

           Ksp = [ Cu²⁺ ] [ S²⁻ ] = S × S = S²

         S² = 6 × 10⁻¹⁶

        S = √6 × 10⁻¹⁶

           = 2.45 × 10⁸ mol L⁻¹

maximum molarity of CuS in aqueous solution = 2.45 × 10⁻⁸ mol L⁻¹

Hope it helps you !!