Question

If the solutions of linear equtions 6x+14y
+8=0 is (k²,k) then find the value of x

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

-1

Step-by-step explanation:

Since solutions are of form (k^2,k), 6k^2+14k+8 = 0 should be true.

Factorising this, we get:

6k^2+14k+8=0

,6k^2+6k+8k+8=0

,6k(k+1)+8(k+1)=0

(6k+8)(k+1)=0

Therefore, k=-4/3 and -1

Applying the solutions of k in the initial equation, we find that when x and y are -1, the equation is satisfied.

Therefore, -4/3 is rejected.

x = -1

Hope this helps.. :D