Question

If the source and reciver are at rest realative to each other but the wave medium is moving realative to them, will the reciver delect wavelength or frequency shift.

Answer 1

No

Explanation:

The expression for the apparent frequency when there is a relative motion between receiver and source is as follows;

$f'=f\frac{v\pm v_{r}}{v\pm v_{s}}$

Here, f' is the apparent frequency, f is the actual frequency, v is the velocity of the sound, $v_{s}$ is the velocity of the source and $v_{s}$ is the velocity of the receiver.

According to the given problem, the source and receiver are at rest relative to each other.

$v_{s}=v_{r}$.

Put $v_{s}=0$ and $v_{r}=0$.

f'= f

Therefore, there is no change in the frequency or frequency shift or wavelength shift.

The expression for the apparent frequency when there is relative motion between receiver and source when the wave medium is moving relative to them is as follows;

$f'=f\frac{v+v_{m}\pm v_{r}}{v+v_{m}\pm v_{s}}$

Here, $v_{m}$  is the velocity of the medium.

Put $v_{s}=0$ and $v_{r}=0$.

f\sim f'

Therefore, there is no shift in frequency or wavelength shift.