if the source is moving away from the observer , then the apparent frequency.........
a) will increase
b)will remain the same
c)will be zero
d) will decrease
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Answered by
35
d) will decrease ...
abcd145:
d)
Answered by
15
Answer : (d) decreases
It's depends upon Doppler effect .
According to Doppler effect
![\bold{\nu=\nu_0[\frac{v\pm v_0}{v\pm v_s}]} \bold{\nu=\nu_0[\frac{v\pm v_0}{v\pm v_s}]}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cnu%3D%5Cnu_0%5B%5Cfrac%7Bv%5Cpm+v_0%7D%7Bv%5Cpm+v_s%7D%5D%7D)
Here ν is apparent frequency , ν₀ is initial frequency ,V₀ is velocity of observer and Vs is velocity of source
Now, when source is moving away from the observer and observer is in rest
Means V₀ = 0 , for towards , we should use V + Vs
Then, ν = v₀( V + 0)/(V + Vs)
ν = ν₀V/(V + Vs) means ν < ν₀
Hence, apparent frequency decreases
It's depends upon Doppler effect .
According to Doppler effect
Here ν is apparent frequency , ν₀ is initial frequency ,V₀ is velocity of observer and Vs is velocity of source
Now, when source is moving away from the observer and observer is in rest
Means V₀ = 0 , for towards , we should use V + Vs
Then, ν = v₀( V + 0)/(V + Vs)
ν = ν₀V/(V + Vs) means ν < ν₀
Hence, apparent frequency decreases
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