Question

If the Spearman's Rank Correlation Coefficient is 0.88 when D2 = 20, where D is the
difference between the ranks, then find N, the number of observations in pairs of the
variables.
​

Answer 1

Step-by-step explanation:

r = 1 - 6d²/ n(n²-1)

0.88= 1 - 6×20 / n(n²-1)

0.88 [ n(n²-1) ] = n(n²-1) - 120

- 0.12 [ n(n²-1) ] = -120

n(n²-1) = 1000