if the speed of a driver on entering the water decreases by half, by how much will his kinetic energy decrease?
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We know the formula for Kinetic energy = 1/2 mv^2
If the speed of a driver on entering the water decreases by half i.e Final speed becomes v/2
KE new = 1/2m(v/2)^2 = 1/2m×(v^2/4)
i.e 1/4th of the initial kinetic energy.
Therefore the final kinetic energy would be 1/4th i.e 25% of the initial kinetic energy.
Hence it will decrease by 75%.
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Answer:
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Explanation:
Therefore the final kinetic energy would be 1/4th i.e 25% of the initial kinetic energy. Hence it will decrease by 75%.
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