Question

If the speed of an object is halved ,what will be the change in kinetic energy

Answer 1

Answer:

1/4th the original

Explanation:

$ke = m {v}^{2} \div 2$

v became v/2

so new ke = 1/2*m(v/2)^2

1/2*mv/4

=1/4 of initial kinetic energy

hope it is helpful